The solution set of the inequality `1/(x-2)-1/xlt=2/(x+2)` is `(-alpha,beta]uu(gamma,alpha)uu[delta,oo),` then

The solution set of the inequality (1)/(x-2)-(1)/(x)<=(2)/(x+2) is (-alpha,beta]uu(gamma,alpha)uu[delta,oo), then

The solutin set of the inequlity (1)/(x-2)-1/xle(2)/(x+2)is (-alpha,beta]uu(gamma,alpha)uu[delta,oo),then (A) a+beta+gamma+delta=5 (B) alphabetagammadelta=-4 (C) betadelta=-2 (D) alphabetagamma=0

The solutin set of the inequlity (1)/(x-2)-1/xle(2)/(x+2)is (-alpha,beta]uu(gamma,alpha)uu[delta,oo),then (A) a+beta+gamma+delta=5 (B) alphabetagammadelta=-4 (C) betadelta=-2 (D) alphabetagamma=0

If the solution of the inequality (x^(2)-x-1)(x^(2)-x-7)<-5 is x in(alpha,beta)uu(gamma,delta) then find the value of alpha+beta+gamma+delta

If solution set of Inequality (x^(2)+x-2)(x^(2)+x-16)ge -40 is x epsilon(-oo, -4]uu[a,b]uu[c,oo) then a+b-c is

If solution set of Inequality (x^(2)+x-2)(x^(2)+x-16)ge -40 is x epsilon(-oo, -4]uu[a,b]uu[c,oo) then a+b-c is

The solution of the inequality (tan^(-1)x)^(2)-3tan^(-1)x+2>=0 is- a.(-oo,tan1]uu[tan2,oo)b*(-oo,tan1] c.(-oo,-tan1]uu[tan2,oo)d.[-1,1]-(-(sqrt(2))/(2),(sqrt(2))/(2))

The solution set of the inequality max {1-x^(2),|x-1|}<1 is (-oo,0)uu(1,oo) (b) (-oo,0)uu(2,oo)(0,2)(d)(0,2)

The solution set of the inequality max {1-x^2,|x-1|}<1 is (-oo,0)uu(1,oo) (b) (-oo,0)uu(2,oo) (0,2) (d) (0,2)