If `z =-1` then principal value of `arg (z^(2/3))` is equal to

If z=-1 , the principal value of arg. (z^(2//3)) is equal to :

The principal value of arg(z) lies in the interval :

Complex numbers z_(1) and z_(2) lie on the rays arg(z1) =theta and arg(z1) =-theta such that |z_(1)|=|z_(2)| . Further, image of z_(1) in y-axis is z_(3) . Then, the value of arg (z_(1)z_(3)) is equal to

Complex numbers z_(1) and z_(2) lie on the rays arg(z1) =theta and arg(z1) =-theta such that |z_(1)|=|z_(2)| . Further, image of z_(1) in y-axis is z_(3) . Then, the value of arg (z_(1)z_(3)) is equal to

If arg(z_(1))=(2pi)/3 and arg(z_(2))=pi/2 , then find the principal value of arg(z_(1)z_(2)) and also find the quardrant of z_(1)z_(2) .

If arg(z_(1))=(2pi)/3 and arg(z_(2))=pi/2 , then find the principal value of arg(z_(1)z_(2)) and also find the quardrant of z_(1)z_(2) .

For z= sqrt3-i , find the principal, value arg(z)

For z= sqrt3-i , find the principal, value arg(z)

If z =(-2)/(1+sqrt3i), then the value of arg(z) is-