Find gof and fog, if `f : R ->R`and `g : R ->R`are given by `f(x) = cos x`and `g(x)=3x^2`. Show that `gof!=fog`.

Explanation

To solve the problem, we need to find the compositions of the functions \( f \) and \( g \), specifically \( g \circ f \) and \( f \circ g \), and show that they are not equal.

### Step 1: Define the Functions
We have:
- \( f(x) = \cos x \)
- \( g(x) = 3x^2 \)

### Step 2: Find \( f \circ g \)
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