`H_(2)O_(2)` is used as bleaching reagent because on dissociation it gives oxygen
`(H_(2)O_(2) to H_(2)O+(1)/(2)O_(2))`
"Chachi420" used `H_(2)O_(2)` solution to bleach her hair and she required `2.24L O_(2)` gas at 1atm and 273K. She has a `H_(2)O_(2)` solution labelled '5.6V' then what volume of such solution must she required to bleach her hair?