An electron in the beam of a TV picture tube is accelerated by a potential difference of `2.00 kV`. Then, it passes through region of transverse magnetic field, where it moves in a circular arc with radius `0.180 m`. at is the magnitude of the field?

A particle of mass m carrying charge q is accelerated by a potential difference V. It enters perpendicularly in a region of uniform magnetic field B and executes circular arc of radius R, then q/m equals

A particle of mass m carrying charge q is accelerated by a potential difference V. It enters perpendicularly in a region of uniform magnetic field B and executes circular arc of radius R, then q/m equals

Electron moving at right angle to a uniform magnetic field complete a circular orbit of 10^(-2) m radius in 10^-10s . What is the magnitude of magnetic field.

A beam of electrons is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field where it moves in a circle of radius r . It would have moved in a circle of radius 2r if it were initially accelarated through a potential difference

A charge q is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field, where it moves in a circle of radius r. Then potential difference required to move it in a circle of radius 2 r is

A charge q is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field , where it moves in a circle of radius r . The potential difference required to move it in a circle of radius 2 r is

A charge q is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field , where it moves in a circle of radius r . The potential difference required to move it in a circle of radius 2 r is

An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is