Home
Class 12
CHEMISTRY
For the reaction : C(2)H(5)OH(l)+3O(2)(g...

For the reaction : `C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(g)`
if `Delta U^(@)= -1373 kJ mol^(-1)` at `298 K`. Calculate `Delta H^(@)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The value of enthalpy change (Delta H) for the reaction : C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 2CO_(2)(g) + 3H_(2)O(l) at 27^(@)C is - 1366.5 kJ mol^(-1) . The value of internal energy change for the above reaction at the temperature will be :

For the reaction C_(2)H_(4)(g)+3O_(2)(g) rarr 2CO_(2) (g) +2H_(2)O(l) , Delta E=-1415 kJ . The DeltaH at 27^(@)C is

For the reaction : C_(2)H_(4)(g) + 3 O_(2)(g) rarr 2 CO_(2)(g) + 2 H_(2)O(l) at 298 K, Delta U = - 1415 kJ . If R = 0.0084 kJ K^(-1) . Then Delta H is equal to

For the reaction : C_(3)H_(8)(g) + 5O_(2) rarr 3CO_(2)(g) + 4H_(2)O(l) a constant temperature, Delta H - Delta U is

For the reaction, C_(2) H_(4) (g) + 3O(2) (g) to 2 CO_(2) (g) + 2H_(2) O(I), Delta E = -1415 KJ. then Delta H at 27^(@) C is

Calculate the enthalpy of formation of methanol from the following data, CH_(3)OH(l) + (3)/(2)O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l) ….(i) " "Delta H^(@) = -726.4 kJ mol^(-1) C"(graphite)" + O_(2)(g) rarr CO_(2)(g) ….(iii) " "Delta H^(@) = -393.5 kJ mol^(-1) H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) ....(iii) " "Delta H^(@) = -285.8 kJ mol^(-1) .

Compounds with carbon-carbon double bond, such as ethylene, C_(2)H_(4) , add hydrogen in a reaction called hydrogenation. C_(2)H_(4)(g)+H_(2)(g) rarr C_(2)H_(6)(g) Calculate enthalpy change for the reaction, using the following combustion data C_(2)H_(4)(g) + 3O_(2)(g) rarr 2CO_(2)(g) + 2H_(2)O(g) , Delta_("comb")H^(Θ) = -1401 kJ mol^(-1) C_(2)H_(6)(g) + 7//2O_(2)(g)rarr 2CO_(2) (g) + 3H_(2)O(l) , Delta_("comb")H^(Θ) = -1550kJ H_(2)(g) + 1//2O_(2)(g) rarr H_(2)O(l) , Delta_("comb")H^(Θ) = -286.0 kJ mol^(-1)

Compounds with carbon-carbon double bond, such as ethylene, C_(2)H_(4) , add hydrogen in a reaction called hydrogenation. C_(2)H_(4)(g)+H_(2)(g) rarr C_(2)H_(6)(g) Calculate enthalpy change for the reaction, using the following combustion data C_(2)H_(4)(g) + 3O_(2)(g) rarr 2CO_(2)(g) + 2H_(2)O(g) , Delta_("comb")H^(Θ) = -1401 kJ mol^(-1) C_(2)H_(6)(g) + 7//2O_(2)(g)rarr 2CO_(2) (g) + 3H_(2)O(l) , Delta_("comb")H^(Θ) = -1550kJ H_(2)(g) + 1//2O_(2)(g) rarr H_(2)O(l) , Delta_("comb")H^(Θ) = -286.0 kJ mol^(-1)