The position vector of the centre of the circle `|barr|,vecr.(i+j+k)=3sqrt(3)` is

The position vector of the centroid of the triangle formed by the points i + j + k, i - j + k, -i + j + k is

The position vector of the centroid of the Delta ABC is 2i + 4j + 2k . If the position vector of the vertex A is 2i + 6j + 4k, then the position vector of midpoint of BC is a)2i + 3j + k b)2i + 3j - k c)2i - 3j - k d) -2i - 3j - k

The positon vector of the centroid of the triangle ABC is 2i+4j+2k . If the position vector of the vector A is 2i+6j+4k., then the position vector of midpointof BC is (A) 2i+3j+k (B) 2i+3jk (C) 2i-3j-k (D) -2i-3j-k

The positon vector of the centroid of the triangle ABC is 2i+4j+2k . If the position vector of the vector A is 2i+6j+4k., then the position vector of midpointof BC is (A) 2i+3j+k (B) 2i+3jk (C) 2i-3j-k (D) -2i-3j-k

If the position vectors of the vertices of a triangle are 2i - j + k, i - 3j - 5k, 3i - 4j - 4k then it is

If the position vectors of A, B are 2i + 3j + k and 3i - j + 4k repectively then the position vector of the point which divides AB in the ratio 3 : 2 is

Show that the lines vecr= (hat i+hat j+hat k)+t(hat i-hat j+hat k) and vecr= (3 hati-hatk)+s(4 hat j-16 hat k) intersect and find the position vector of their point of their point of intersection.

If the position vectors of the points A and B respectively are i+2j-3k and j-k find the direction cosines of AB