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int[1+cos^2x]/[1-cos2x].dx...

`int[1+cos^2x]/[1-cos2x].dx`

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int(1+cos 2x)/(1-cos 2x)dx

int(1+cos 2x)/(1-cos 2x)dx

Knowledge Check

  • int(1+cos^(2)x)/(1-cos2x)dx=

    A
    `-cotx-(x)/(2)+c`
    B
    `cotx+(x)/(2)+c`
    C
    `cotx-(x)/(2)+c`
    D
    `-cotx+(x)/(2)+c`

  • Match the following. I. int (sin x)/(1+cos 2x)dx= " " a) tan x-(1)/(2) x+c II int (1)/(1-cos2x)dx= " " b)- cot x-(1)/(2)x+c III. int (1+cos^(2)x)/(1-cos2x)dx= " " c) (1)/(2)secx+c IV. int (1+sin^(2)x)/(1+cos2x)dx= " " -d) (1)/(2)cotx+c

    A
    a,b,c,d
    B
    b,c,a,d
    C
    d,a,b,c
    D
    a,b,c,a

  • int (1+cos 2x)/(1-cos 2x) dx =

    A
    minus cot x + x
    B
    cot x - x
    C
    log (1-cos 2x)
    D
    minus cot x -x

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    Evaluate the following integrals: (i) int((1-cos2x)/(1+cos2x))dx (ii) int((1+cos2x)/(1-cos2x))dx

    Evaluate the following inegrals int(1-cos2x)/(1+cos2x)dx

    Evaluate the following integrals : int(1-cos2x)/(1+cos2x)dx

    Evaluate the following integrals : int(1-cos2x)/(1+cos2x)dx

    2int(1+cos^(2)x)/(1+cos2x)dx=

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