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In the given fig O is centre of circle, ...

In the given fig O is centre of circle, `/_ACO =35^@`and `/_ABO =45^@`, then what is the value of `/_BOC`

Text Solution

Verified by Experts

from the given figure we can conclude that
`/_ BAC = 45^@ + 35^@`
`= 80^@`
Now as we can see that
`/_ BOC = 2/_BAC`
`/_BOC = 2 xx 80^@`
`= 160^@`
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