The lengths of the two sides of a right triangle containing the right angle differ by `2cm.` If the area of the triangle is `24cm^2.` Find the perimeter of the triangle.

The sides ( in cm ) of a right triangle containing the right angle are 3(x+1) and (2x-1). If the area of triangle is 30sq.cm, find the sides of the triangle.

Represent the following problem situations in the form of Quadratic Equations :- The sides (in cm) of a right triangle containing the right angle are 5x and {3x - 1). If the area of the triangle is 60 cm^2 , find the sides of the triangle.

If the difference between the two sides of a right-angled triangle is 2 cm and the area of the triangle is 24 cm^(2) , find the perimeter of the triangle.

The sides of a right angled triangle containing the right angle are 4x cm and (2x-1) cm. If the area of the triangle is 30cm^(2) calculate the lengths of its sides.

The sides of a right angled triangle containing the right angle are 4x cm and (2x-1) cm. If the area of the triangle is 30cm^(2) calculate the lengths of its sides.

The difference between the sides at right angles in a right - angled triangle is 14 cm . The area of the trangle is 120 cm^(2) . Calculate the perimeter of the triangle.

The sides of a right-angied triangle forming right angle are in the ratio 5: 12. If the area of the triangle is 270 cm^2 , then the length of the hypotenuse is

the difference between the sides ar right angles in right- angled triangle is 7 cm . The area of the triangle is 60 cm^(2) .Find its perimeter .

The sides of a right angled triangle containing the right angle are 5x cm and ( 3x-1) cm . If the area of the triangle is 60 sq . Cm the length of the sides of the triangles are