In `CGS` system the magnitude of the force is 100 dynes. In another system where the fundamental physical quantities are kilogram, meter and minute, Find the magnitude of the force.

Options

A. `0.036`
B. `0.36`
C. `3.6`
D. `36`

Answer

C

Explanation

`n_(2) = n_(1)((M_(1))/(M_(2)))^(1)((L_(1))/(L_(2)))^(1)((T)/(T_(2)))^(-2)`
`= 100((g)/(kg))^(1)((cm)/(m))^(1)((s)/(min))^(-2)`
`= 100((g)/(10^(3)g))^(1)((cm)/(10^(2) cm))^(1)((s)/(60 s))^(-2)`
`= (3600)/(10^(2))= 3.6`