If energy E, length L, and time T are taken as fundamental quantities .The dimensional formula of gravitational constant is

Options

A. `[FL^(6)E^(-2)]`
B. `[FL^(5)T^(-1)]`
C. `[E^(2)FL^(6)T^(0)]`
D. `[E^(2)F^(-1)L^(6)T^(5)]`

Answer

a

Explanation

`:. E= [ML^(2)T^(-2)]`
`rArr M = [EL^(-2)T^(2)]`
`:' F = (Gm_(1)m_(2))/(r^(2))`
`rArr [G] (Fr^(2))/(m_(1)m_(2))= [FL^(2)M^(-2)]`
`[Fl^(2)][EL^(-2)T^(-2)]^(-2)= [FL^(6)E^(-2)]`