The resistance of a metal is given by `R = V//I` , where `V` is potential difference and `I` is current . In a circuit , the potential difference across resistance is `V = ( 8 +- 0.5) V` and current in resistance , `I = ( 4 +- 0.2)A`. What is the value of resistance with its percentage error?

Options

A. `4 +- 16.25 %`
B. `4 +- 6.25 %`
C. `4 +- 10 %`
D. `4 +- 8 %`

Answer

a

Explanation

We know that `R = V//l = 8//2 = 4 Omega` percentage error in
`V` is `(0.5)/(8) xx 100 = 6.25`
percentage error in `l` is `(0.2)/(2) xx 100 = 10` Now, add up the percentage error and get the answer.