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In an experiment , the following observa...

In an experiment , the following observations were recorded:
`L = 2.820 m , M = 3.00 kg , l = 0.087 cm , diameter , D = 0.041 cm`. Taking ` g = 9.81 m s^(-2)` and using the formula , `Y = ( 4MgL)/( pi D^(2) l)` , find the maximum permissible error in `Y`.

A

`7.96%`

B

`4.56%`

C

`6.50%`

D

`8.42%`

Text Solution

Verified by Experts

The correct Answer is:
C
`Y= (4MgL)/(pi D^(2)l)` so maximum permissible error in Y is
`(Delta Y)/(Y) xx 100= ((Delta M)/(M) + (Delta g)/(g) + (Delta L)/(L) + (2 Delta D)/(D) + (Delta I)/(I))xx100`
`= ((1)/(300) + (1)/(981) +(1)/(2820)+ 2 xx (1)/(41) +(1)/(87)) xx 100`
`= 0.065 xx 100 = 6.5%`
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