A wire has a mass `0.3+-0.003g`, radius `0.5+-0.005mm` and length `6+-0.06cm`. The maximum percentage error in the measurement of its density is

Options

A. `1`
B. `2`
C. `3`
D. `4`

Answer

d

Explanation

Density , `rho= (M)/(V) = (M)/(pui r^(2)L)`
`rArr (Delta rho)/(rho) =(Delta M)/(M) + 2 (Delta r)/(r ) + (Delta L)/(L)`
` = (0.003)/(0.3)+ 2 xx (0.005)/(0.5) + (0.06)/(6)`
`= 0.01 + 0.02 + 0.01 = 0.04`
`:.` Perecentage error `= (Delta rho)/(rho) xx 100 = 0.04 xx 100 = 4%`