In a circuit potential difference across resistence `V = (4 +- 0.25)V `and curent in resistence ,`f = (1 +- 0.1)` what is the value of resistence with its percentage error

Options

A. `(4 +- 0.4)Omega`
B. `4 Omega + 16.25%`
C. `4 Omega + 18.25%`
D. `4 Omega + 22.25%`

Answer

b

Explanation

`E_(0) = (V_(0))/(I_(0)) = (4)/(1) = 4 Omega`
`(DeltaR)/(R ) = (Delta V)/(V) + (Delta I)/(I)`
`= (0.25)/(4) + (0.1)/(1.0) = 0.1625`
`R = 4Omega + 16.25%`