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The focal f to a mirror is given by (1)/...

The focal f to a mirror is given by `(1)/(f) = (1)/(u) + (1)/(v)` where u and v represent object and image distance respectively then

A

`(Delta f)/(f) = (Delta u)/(u) + (Delta v)/(v)`

B

`(Delta f)/(f) = (Delta u)/(v) + (Delta v)/(u)`

C

`(Delta f)/(f) = (Delta u)/(u) + (Delta v)/(v)- (Delta(u +v))/(u +v)`

D

`(Delta f)/(f) = (Delta u)/(u) + (Delta v)/(v)+ (Delta u)/(u + v) +(Delta v)/(u+v)`

Text Solution

Verified by Experts

The correct Answer is:
D
`f = (uv)/(u+v),(Delta f)/(f) = (Delta u)/(u)+(Delta v)/(v) +(Delta(u+v))/(u+v)`
`= (Delta u)/(u) +(Delta v)/(v) +(Delta u)/(u+v)+ (Deltav)/(u+v)`
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Knowledge Check

  • Find the value of f in (1)/(f) = (1)/(u) + (1)/(v) wen u = 15 and v = 10.

    A
    `-6`
    B
    `1//6`
    C
    `6`
    D
    `- ((1)/(6)) `

  • If (1)/(f) = (1)/(u) +(1)/(v) then make v as the subject of the formula.

    A
    ` v= (u-f)/(uf)`
    B
    ` v= (f-u)/(fu)`
    C
    ` v= (uf)/(u-f)`
    D
    ` v= (uf)/(u+f)`

  • Directions for questions : Select the correct answer from the given options. The focal length of a mirror is given by the formula (1)/(f) = (1)/(mu) + (1)/( v) . Make f fast the subject of the formula. If u = 20 "cm" and v = 30 "cm" , then find f . The following seeps are involved in solving the above problem. Arrange chem in sequential order. A Given (1)/(f) = (1)/( u ) + (1)/(v) B rArr f = (uv)/( u+v) C f = (20 xx 30)/( 20 + 30) = (600)/(50) = 12 cm D rArr (1)/( f) = (v+u)/( uv)

    A
    ADBC
    B
    BADC
    C
    ACDB
    D
    DBAC

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