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If (A)/(mu(0)) has the dimensions [MLT^(...

If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?

A

square of electric flux

B

square of magnitic flux

C

square of electric field

D

square of energy

Text Solution

Verified by Experts

The correct Answer is:
c

`[(A)/(mu_(0))]= [(epsilon_(0)A)/(epsilon_(0)mu_(0))]= ([epsilon_(0)d])/(1//"speed of light"]^(2)`
`= [ML^(2)T^(-2)]` (Given)
`[epsilon_(0) A] = [ML^(-1)T^(-2)] = ([ML^(2)T^(-2)])/([L^(2)])`
So `epsilon_(0)A` is the energy per volume
Thus A should be `E^(2)`
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