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The currect voltage relation of a diode ...

The currect voltage relation of a diode is given by `1 = (e^(van v//T) -1 )mA` where the applied volied `V` is in volts and the tempetature `T` is in degree kelvin if a student make an error meassurting `+- 01 V` while measuring the current of `5 mA at 300 K` what be the error in the value of current in `mA`

A

`0.5 mA`

B

`0.05 mA`

C

`0.2 mA`

D

`0.02 mA`

Text Solution

Verified by Experts

The correct Answer is:
c

Given `5 = e^(1000_(T)^(L)) - 1m`
`rArr e^(1000) (V)/(T) = 6`…(i)
Again, `1 = e^(1000_(T)^(L)) - 1`
`(dl)/(dV) = e^((1000)/(T) V) (1000)/(T)`
`dl = (1000)/(T) e ^((1000)/(T))Vdv`
Using (i) `Delta I = (1000)/(T) xx 6 xx 0.01= (60)/(T) = (60)/(300) = 0.2 mA`
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