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The unit of Stefan's constant sigma is...

The unit of Stefan's constant `sigma` is

A

`W m^(-2)K^(-1)`

B

`W m^(2)K^(-4)`

C

`W m^(-2)K^(-4)`

D

`W m^(-2)K^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
c
Stefan's low is `E = sigma (T^(4)) rArr sigma = (E )/(T^(4)`
where `E = ("energy")/("Area" xx "time") = (Wm)/(m^(2))`
`sigma = (W - m^(-2))/(K^(-4)) = W- m^(-2)K^(-4)`
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The value of Stefan's constant is sigma =5.76xx 10^(-8) J s^(-1) m^(-2)K^(-4). Find its value in cgs system.

The value of Stefan's constant is sigma = 5.67xx10^(-8)Js^(-1)m^(2)K^(-4) . Find its value in CGS system, where joule (J) and erg are the units of energy in SI and CGS system, respectively.

Knowledge Check

  • Unit of Stefan's constant is

    A
    `Js^(-1)`
    B
    `Jm^(-2)s^(-1)K^(-4)`
    C
    `Jm^(-2)`
    D
    `Js`

  • The MKS unit of Stefan's constant is

    A
    Watt/ `m^2-K^4`
    B
    Watt `m^2- K^4`
    C
    Watt/ `m^2 - K`
    D
    Watt/`m^2`

  • The value of Stefan's constant is

    A
    `5.67 xx10^(-8)W//m^(2)-K^(4)`
    B
    `5.67 xx10^(-5)W//m^(2)-K^(4)`
    C
    `5.67 xx10^(-11)W//m^(2)-K^(4)`
    D
    None of these

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