In the dimension of a physical quantities are given by `M^(0)L^(1)T^(0)` , then the physical quantity will be

Options

A. pressure if `a = 1, b = -1, c = -2`
B. Velocity if `a = 1, b = 0, c = -1`
C. acceleration if `a = 1, b = 1, c = -2`
D. force if `a = 0, b = -1, c = -2`

Answer

a

Explanation

(i) Dimension of velocity `= [M^(0)L^(1)T^(-1)]`
Here `a = 0, b = 1 , c = -1`
(ii) Dimension of acceleration `= [M^(0)L^(1)T^(-2)]`
Here `a = 0, b = 1 , c = -2`
(iii) Dimension of Force `= [M^(0)L^(1)T^(-2)]`
Here `a = 0, b = 1 , c = -2`
(iv) Dimension of pressure `= [M^(0)L^(-1)T^(-2)]`
Here `a = 0, b = -1 , c = -2`
The physical quantities is pressure.