Using `mass (M), "length"(L) , time (T)` and current` (A) `as fundamental quantites the demension of permeability is

Options

A. `[MLT^(-2)A]`
B. `[M^(-1)L^(-2)T^(4)A^(2)]`
C. `[MLT^(-1)A]`
D. `[ML^(2)T^(-1)A^(2)]`

Answer

b

Explanation

From Coulomb's law , `F = (1)/(4 pi epsilon_(0)) - (q_(1) q_(2))/(r^(2))`
`rArr epsilon_(0) = (1)/(4 pi) - (q_(1) q_(2))/(Fr^(2))`
`:.` Dimensions of pormittivity
`epsilon_(0)= ("Dimensions of" q^(2))/("Dimensions of F" xx "Dimensions of" r^(2))`
`[epsilon_(0)] = ([A^(2)T^(2)])/([MLT^(-2)][L^(2)]) = [M^(-1)L^(-3)T^(4)A^(2)]`