In `CGS` system the magnitude of the force is 100 dynes. In another system where the fundamental phyical quamtities are kilogram , meter , and minute, find the magnitude of the force.

Options

A. `0.036`
B. `0.36`
C. `3.6`
D. `36`

Answer

c

Explanation

`n_(2) =n_(1) ((M_(1))/(M_(2)))((L_(1))/(L_(2)))((T)/(T_(2)))^(-2)`
`= 100 ((gm)/(kg)) ^(1) ((cm)/(m))^(1) ((sec)/(min))^(-2)`
`= 100 ((gm)/(10^(2)gm)) ^(1) ((cm)/(10^(2)cm))^(1) ((sec)/(60 sec))^(-2)`
`n_(2) = (3600)/(10^(3)) = 3.6`