If the unit of velocity is run , the unit of time is second and unit of force is strength in a hyperthetical system of unit in this system of unit the unit of mass is `("strength") //("second")^(2) ("run")^(2)`
Thus, `x = 1, y = 1` and `z = -1`
`(y)/(x) = 1`

Options

A. `3`
B. `5`
C. `6`
D. `1`

Answer

d

Explanation

`:' F = ma`
`rArr m= (F)/(a) = ("Force") //("Change in velocity")/("time")`
`= ("Force" xx "time")/("Change in velocity")`
`= ("strength")("sec")("run")^(-1)`
`:. (y)/(x) = 1`