If force F velocity V and time T are taken as fundamental units, find the power of dimensions of force in the dimensional formula of pressure

Options

A. `3`
B. `5`
C. `6`
D. `1`

Answer

d

Explanation

`[F] = [MLT^(-2)]`
`rArr [v] = [LT^(-1)]`
`:. [L] = [vT]`
`:. [M] = ([F])/([LT^(-2)]) = ([F])/([vT]xx [T^(-2)]) = [Fv^(-1)T]`
`:. "Pressure" = [ML^(-1)T^(-2)]`
`[Fv^(-1)T] [vT]^(-1) [T^(-2)] = [Fv^(-2)T^(-2)]`
Thus, in the dimensional formula of pressure dimension of force is `1`.