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An object of m kg with speed of v m s^(-...

An object of m kg with speed of v `m s^(-1)` strikes a wall at an angle `theta` and rebounds at the same speed and same angle. Find the magnitude of change in the momentum of object.

A

`2 mv cos theta`

B

`2mv sin theta`

C

0

D

`2 mv`

Text Solution

Verified by Experts

The correct Answer is:
A
`vec(P)_(1)= mv sin theta hat(i)-mv cos theta hat(j)`
and `vec(P)_(2)= mv sin theta hat(i)+mv cos theta hat(j)`
So change in momentum
`vec(DeltaP)= vec(P)_(2)-vec(P)_(1)= 2mv cos theta hat(j), |Deltahat(P)|= 2 mv cos theta`
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