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If |vec(A)xxvec(B)|=|vec(A).vec(B)|, the...

If `|vec(A)xxvec(B)|=|vec(A).vec(B)|`, then the angle between `vec(A)` and `vec(B)` will be

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

`|vec(A)xxvec(B)|= vec(A)*vec(B) implies AB sin theta = AB cos thetaimplies tan theta= 1`
`:. theta= 45^(@)`
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