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A body is in equilibrium under the actio...

A body is in equilibrium under the action of three coplanar forces `P,Q and R` as shown in figure. Select the correct statement.

A

`P/(sin alpha)=Q/(sin beta)=R/(sin gamma)`

B

`P/(cos alpha)=Q/(cos beta)=R/(cos gamma)`

C

`P/(tan alpha)=Q/(tan beta)=R/(tan gamma)`

D

`P/(sin beta)=Q/(sin gamma)=R/(sin alpha)`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Lami's theorem
`P/(sin alpha)=Q/(sin beta)=R/(sin gamma)`
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Knowledge Check

  • A body is inequibrium under the action of three coplanar forces, then

    A
    they must act in a straight line
    B
    they must meet in point
    C
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    D
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  • For the situation shown in the figure, select the correct statements (s).

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    D
    Potential at point B due to induced charges is `-qR//4piepsilon_0(d+R)d`

  • Three identical bulbs are connected as shown in figure. Choose the correct statement.

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    All bulbs are in a series combination.
    B
    If bulb R is removed, bulbs P and Q will still glow.
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    D
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