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If vec(A) and vec(B) are two vectors, wh...

If `vec(A)` and `vec(B)` are two vectors, which of the following is not correct?

A

`vec(A)+vec(B)= vec(B)+vec(A)`

B

`vec(A).vec(B)= vec(B).vec(A)`

C

`vec(A)xxvec(B)= vec(B)xxvec(A)`

D

`vec(A)-vec(B)= -(vec(B)-vec(A))`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement about the vectors \(\vec{A}\) and \(\vec{B}\) is not correct, let's analyze each option step by step. ### Step 1: Analyze the first option **Statement:** \(\vec{A} + \vec{B} = \vec{B} + \vec{A}\) - This statement represents the commutative property of vector addition. - Vectors can be added in any order, so this statement is **correct**. ### Step 2: Analyze the second option **Statement:** \(\vec{A} \cdot \vec{B} = \vec{B} \cdot \vec{A}\) - This statement represents the commutative property of the dot product. - The dot product of two vectors is also commutative, so this statement is **correct**. ### Step 3: Analyze the third option **Statement:** \(\vec{A} \times \vec{B} = \vec{B} \times \vec{A}\) - This statement represents the cross product of two vectors. - The cross product is not commutative; in fact, \(\vec{A} \times \vec{B} = -(\vec{B} \times \vec{A})\). - Therefore, this statement is **not correct**. ### Step 4: Analyze the fourth option **Statement:** \(\vec{A} - \vec{B} = -\vec{A} + \vec{B}\) - This statement can be rearranged to show that \(\vec{A} - \vec{B} = -(\vec{B} - \vec{A})\), which is a valid representation of vector subtraction. - Thus, this statement is **correct**. ### Conclusion The statement that is **not correct** is: \[ \vec{A} \times \vec{B} = \vec{B} \times \vec{A} \]

To determine which statement about the vectors \(\vec{A}\) and \(\vec{B}\) is not correct, let's analyze each option step by step. ### Step 1: Analyze the first option **Statement:** \(\vec{A} + \vec{B} = \vec{B} + \vec{A}\) - This statement represents the commutative property of vector addition. - Vectors can be added in any order, so this statement is **correct**. ...
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