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Weight mg of a block is a force acting d...

Weight mg of a block is a force acting downward toward centre of the earth. A block of mass `1 kg` is placed on an inclined plane as shown in figure. Find the x-component and y-component of weight of the block are

A

`6 N, -8 N`

B

`6 N, 8 N`

C

`8 N, 6 N`

D

`8 N, -6 N`

Text Solution

Verified by Experts

The correct Answer is:
A

`mg = 1xx10= 10N`
From figure, the x-component is
`mg sin 37^(@) = 1xx10xx3/5= 6N`
and y-component is
`-mg cos 37^(@)= -1xx10xx4/5= -8 N`
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Knowledge Check

  • A horizontal force acting on a block of mass m which is placed on an inclined plane (as shown in the figure). What is the normal reaction N on the block?

    A
    `mgsintheta+Fcostheta`
    B
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  • A block of mass 1 kg is placed on a wedge shown in figure. Find out minimum coefficient of friction between wedge and block to stop the block on it.

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    0.6
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  • Normal reaction N is a force exerted by the surface on the block perpendicular to the surface to contact. A block of mass 1 kg is placed on inclined plane of inclintation 37^(@) as shown in the figure Find the component of normal reaction N= 8 N on the block x-axis and y-axis

    A
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