P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given `P= 1.9318 kg-wt, sin theta_(1)= 0.9659`, the value of R is `(in kg-wt)`

Options

A. `0.9659`
B. 2
C. 1
D. `1/2`

Answer

C

Explanation

`(P)/(sin theta_(1))=(Q)/(sin theta_(2))=(R )/(sin 150^(@))`
`implies (1.93)/(sin theta_(1))= (R )/(sin 150^(@))`
`implies R=(1.93xxsin150^(@))/(sin theta_(1))= (1.93xx0.5)/(0.9659)=1`