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If v = x^2 - 5x + 4, find the accelerati...

If `v = x^2 - 5x + 4`, find the acceleration of the particle when velocity of the particle is zero.

A

zero

B

2

C

3

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`a = (dv)/(dt) = (2 x - 5) (dx)/(dt)`
`a = (2 x - 5) v`
when `v = 0, a = 0`.
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