A particle is moving eastwards with a velocity of ` 5 m//s`. In `10 s` the velocity changes to `5 m//s` northwards. The average acceleration in this time is

Options

A. Zero
B. `(1)/(sqrt(2)) m//s^2 N-W`
C. `(1)/(sqrt(2)) m//s^2 N- E`
D. `(1)/(sqrt(2)) m//s^2 S-W`

Answer

B

Explanation

`Delta v = 2 v sin ((theta)/(2)) = 2 xx 5 xx sin 45^@ = (10)/(sqrt(2))`
`:. a = (Delta v)/(Delta t) = (10//sqrt(2))/(10) = (1)/(sqrt(2)) m//s^2`.