A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes `20 m//s` and in tenth second it travels a distance of `10 m`. Then the acceleration of the particle will be.

Options

A. `10 m//s^2`
B. `20 m//s^2`
C. `(1)/(5) m//s^2`
D. `3.8 m//s^2`

Answer

B

Explanation

Using `v = u + at`
`rArr 20 = u + a xx 10` ….(i)
and `s_n = u + (a)/(2) (2n - 1)`
`rArr 10 = u + (a)/(2) (2 xx 10 - 1)` ….(ii)
On solving (i) and (ii) we get `a = 20 m//s^2`.