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A body is thrown vertically upward with ...

A body is thrown vertically upward with velocity `u`. The ratio of times at which it is at particular height `h` is `1 : 2`. What is the maximum height reached by the body above point of projection ?

A

`(9//4)h`

B

`(4//3)h`

C

`(9//8) h`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

`H = (u^2)/(2 g)` …(i)
`(t_1)/(t_2) = (1)/(2) rArr 2t_1 = t_2` ….(ii)
`u = (1)/(2) g(t_1 + t_2)` …(iii)
`h = (1)/(2) g t_1 t_2` …(iv)
From (ii),(iii) and (iv) `u^2 = (9gh)/(4)`
Put `u^2` in equation (i) : `H = (9)/(8) h`.
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Knowledge Check

  • A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is

    A
    `u // g`
    B
    `u^(2) // 2g`
    C
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    D
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    C
    `u^(2)//g`
    D
    `u//2g`
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    A
    velocity is not zero but acceleration is zero
    B
    acceleration is not zero but velocity is zero.
    C
    both acceleration and velocity are zero.
    D
    both acceleration and velocity are not zero.
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