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A boy standing at the top of a tower of `20 m`. Height drops a stone. Assuming `g = 10 ms^-2` towards north. The average acceleration of the body is.

A

`20 m//s`

B

`40 m//s`

C

`5 m//s`

D

`10 m//s`

Text Solution

Verified by Experts

The correct Answer is:
A

We have `v = sqrt(2 gh)`
=`sqrt(2 xx 10 xx 20) = sqrt(400) = 20 ms^-1`.
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