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Preeti reached the metro station and fou...

Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time `t_1`. On other days, if the remains stationary on the moving escalator, then the escalator takes her up in time `t_2`. The time taken by her to walk up on the moving escalator will be :

A

`(t_1 t_2)/(t_2 - t_1)`

B

`(t_1 t_2)/(t_2 + t_1)`

C

`t_1 - t_2`

D

`(t_1 + t_2)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the time taken by Preeti to walk up on the moving escalator. We will use the information given about her walking speed on a stationary escalator and the speed of the escalator itself. ### Step-by-Step Solution: 1. **Define Variables**: - Let \( L \) be the length of the escalator. - Let \( v_p \) be Preeti's walking speed. - Let \( v_e \) be the speed of the escalator. - Let \( t_1 \) be the time taken by Preeti to walk up the stationary escalator. - Let \( t_2 \) be the time taken by the escalator to take her up when she is stationary. 2. **Calculate Preeti's Walking Speed**: - When Preeti walks up the stationary escalator, her speed is \( v_p = \frac{L}{t_1} \). 3. **Calculate Escalator Speed**: - When the escalator takes her up while she is stationary, the speed of the escalator is \( v_e = \frac{L}{t_2} \). 4. **Calculate Combined Speed on Moving Escalator**: - When Preeti walks up the moving escalator, her effective speed relative to the ground is the sum of her walking speed and the escalator speed: \[ v_{total} = v_p + v_e = \frac{L}{t_1} + \frac{L}{t_2} \] 5. **Express Total Speed in Terms of Time**: - Let \( t \) be the time taken by Preeti to walk up the moving escalator. The distance covered is still \( L \), so we can express the total speed as: \[ v_{total} = \frac{L}{t} \] 6. **Set Up the Equation**: - Equating the two expressions for total speed: \[ \frac{L}{t} = \frac{L}{t_1} + \frac{L}{t_2} \] 7. **Simplify the Equation**: - Cancel \( L \) from both sides (assuming \( L \neq 0 \)): \[ \frac{1}{t} = \frac{1}{t_1} + \frac{1}{t_2} \] 8. **Find Time \( t \)**: - Taking the reciprocal gives: \[ t = \frac{t_1 t_2}{t_1 + t_2} \] ### Final Answer: The time taken by Preeti to walk up on the moving escalator is: \[ t = \frac{t_1 t_2}{t_1 + t_2} \]

To solve the problem, we need to find the time taken by Preeti to walk up on the moving escalator. We will use the information given about her walking speed on a stationary escalator and the speed of the escalator itself. ### Step-by-Step Solution: 1. **Define Variables**: - Let \( L \) be the length of the escalator. - Let \( v_p \) be Preeti's walking speed. - Let \( v_e \) be the speed of the escalator. ...
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