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A particle moving with uniform accelerat...

A particle moving with uniform acceleration along x-axis has speed `v m//s` at a position `x` metre given `v = sqrt(180 - 16 x)" "(0 lt x lt(180)/(16))`
The acceleration of the particle in `m//s^2` is.

A

`-16`

B

` - 8`

C

8

D

16

Text Solution

Verified by Experts

The correct Answer is:
B
`v^2 = 180 - 16 x`
Taking `(d)/(dx)` of both sides
`(d)/(dx) (v^2) = (d)/(dx) (180 - 16 x) rArr 2v = (dv)/(dx) = -16`
or `a = (vdv)/(dx) = - 8 m//s^2`
Hence acceleration is `- 8 m//s^2`.
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