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A ball is dropped from some height. Afte...

A ball is dropped from some height. After rebound from the floor it ascends to the same height. Draw the velocity-time graph for the given motion.

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To draw the velocity-time graph for a ball dropped from a height and rebounding to the same height, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Motion**: - The ball is dropped from a height \( h \) with an initial velocity \( u = 0 \). - The motion consists of two parts: falling down to the ground and then rebounding back up to the same height. 2. **Analyze the Falling Motion**: - As the ball falls, it accelerates due to gravity. The acceleration \( a = g \) (approximately \( 9.81 \, \text{m/s}^2 \)). - The velocity of the ball just before it hits the ground can be calculated using the equation: \[ v = u + at = 0 + (-gt) = -gt \] - Here, the negative sign indicates the downward direction. 3. **Graph the Falling Motion**: - At \( t = 0 \), the velocity \( v = 0 \). - As time increases, the velocity becomes more negative, indicating that the ball is falling faster. - The graph will be a straight line with a negative slope, starting from the origin (0,0) and moving downwards. 4. **Analyze the Rebound Motion**: - Upon hitting the ground, the ball rebounds with the same speed it had just before hitting the ground, but in the opposite direction (upward). - Thus, the velocity at the moment of rebound is \( v = -v_{\text{impact}} \) (which is positive in the upward direction). 5. **Graph the Rebound Motion**: - After reaching the ground, the velocity will start from the negative value (just before impact) and increase towards zero as it rises. - The graph will then continue to rise above the time axis, reaching a maximum height where the velocity becomes zero again. 6. **Final Graph**: - The complete velocity-time graph will consist of: - A straight line segment sloping downwards from the origin to a negative velocity value (falling). - A straight line segment sloping upwards from that negative velocity value back to zero (rebounding). ### Velocity-Time Graph: - The graph starts at (0,0), slopes downwards to a negative value at the time of impact, and then slopes upwards back to (t, 0) at the maximum height after rebound.

To draw the velocity-time graph for a ball dropped from a height and rebounding to the same height, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Motion**: - The ball is dropped from a height \( h \) with an initial velocity \( u = 0 \). - The motion consists of two parts: falling down to the ground and then rebounding back up to the same height. ...
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