A constant force acting on a body of mass 5kg change its speed from `5ms^(-1)` in 10s without changing the direction of motion. The force acting on the body is

Options

A. `1.5N`
B. 2N
C. `2.5N`
D. 5N

Explanation

To solve the problem, we need to find the force acting on a body of mass 5 kg that changes its speed from 5 m/s to 10 m/s in 10 seconds. We will use Newton's second law of motion and the formula for acceleration.

### Step-by-step Solution:

1. **Identify the Given Data:**
- Mass of the body (m) = 5 kg
- Initial speed (u) = 5 m/s
- Final speed (v) = 10 m/s
- Time (t) = 10 s

2. **Calculate the Acceleration (a):**
- We use the formula for acceleration:
\[ a = \frac{v - u}{t} \]
- Substitute the values:
\[ a = \frac{10 \, \text{m/s} - 5 \, \text{m/s}}{10 \, \text{s}} = \frac{5 \, \text{m/s}}{10 \, \text{s}} = 0.5 \, \text{m/s}^2 \]

3. **Calculate the Force (F):**
- Using Newton's second law, the force can be calculated as:
\[ F = m \cdot a \]
- Substitute the values:
\[ F = 5 \, \text{kg} \cdot 0.5 \, \text{m/s}^2 = 2.5 \, \text{kg m/s}^2 \]
- Since \(1 \, \text{kg m/s}^2\) is equivalent to \(1 \, \text{Newton}\), we can say:
\[ F = 2.5 \, \text{N} \]

4. **Final Answer:**
- The force acting on the body is \(2.5 \, \text{N}\).