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Two block are connected by a string as shown in the diagram. The upper block is hung by another string. `A` force `F` applied on the upper string produces an acceleration of `2m//s^(2)` in the upward direction in both the blocks. If `T` and `T^(t)` be the tension in the two part of the string, then

A

`T=70.8N` and `T^(t)=47.2N`

B

`T=58.8N` and `T^(t)=47.2N`

C

`T=70.8N` and `T^(t)=58.8N`

D

`T=70.8N` and `T^(t)=0

Text Solution

Verified by Experts

The correct Answer is:
A

FBD of mass `2kg` FBD of mass `4kg`
`T-T-20=4` (i) `T'-40=8 (ii)
`"By solving (i) and"` (ii) `T=47.23N` and `T=70.8N`
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