A block is kept on a frictionless inclined surface with angle of inclination `alpha`. The incline is given an acceleration 'a' to keep the block stationary. Then a is equal to

Options

A. `g`
B. `g tanalpha`
C. `g//tanalpha`
D. g`cosecalpha`

Answer

B

Explanation

Let the mass of a block is `m` . It will remain stationary if force acting on it are in equilibrium i.e., `macosalpha = mgsinalpha implies a = g tanalpha`
Here `mgsinalpha` =Pseudo force on block, mg=weight