Three identical cars A,B and C are moving at the same speed on three bridges. The car A goes on a plane bridge, B on a bridge convex upward and C goes on a bridge concave upward. Let `F_A,F_B and F_C` be the normal forces exerted by the cars on the bridges when they are at the middle of bridges

Options

A. `F_(A)` is maximum of the three force.
B. `F_(B)` is maximum of the three force.
C. `F_(C)` is maximum of the three force.
D. `F_(A)=F_(B)=F_(C)`

Answer

C

Explanation

(i) For plane Bridge
`F_(A)=NMg`
(ii) For Convex Upward Bridge
`F_(B)=N=Mg-(Mv^(2))/(r)`
(iii) For Concave Downward Bridge
`N=Mg=(Mv^(2))/(r)`
`F_(C)=(Mv^(2))/(r)+Mg`
`F_(C)gtF_(A)gtF_(B)` .