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A partical of mass `m` is attached to a massless string of length `l` and is oscillating in a vrtical plane with the other end of the string fixed to a rigid support. The tension in the string at a certain instant is `T=kmg` .

A

k can never be geaater than 1

B

k can never be less than 1

C

k can never be equal than 1

D

k can never be geaater than 3

Text Solution

Verified by Experts

The correct Answer is:
D

Maxmum tension will be at lowest point:
`T-mg=(mv^(2))/(r)` implies `T=mg+(mv^(2))/(l)`
`v_(max)=sqrt(2gl)` larr Condition for collision.
`T_(max)=mg+(m(sqrt(2gl)^(2)))/(l)=3mg` .
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