If the blocks are moving as shown in the figure the relation between `a_(1)` , `a_(2)` and `a_(3)` will be.

Options

A. `2a_(1)+2a_(2)+a_(3)=0`
B. `2a_(1)-2a_(2)+a_(3)=0`
C. `2a_(1)-2a_(2)+2a_(3)=0`
D. `2a_(2)-2a_(1)+a_(3)=0`

Answer

D

Explanation

From pulley (3)
`a_(2)=(2a_(1)-a_(3))/(2)`
`2a_(1)=2a_(1)-a_(3)`
`2a_(3)-2a_(1)+a_(3)=0` .