A light string of 70cm has its two ends...

A light string of `70cm` has its two ends tied at the same level `50cm` apart. A force of `100N` is applied at a distance of `30cm` from `P` . The tension in part PR is.

`18N`

`8N`

`0N`

`80N`

Text Solution

Verified by Experts

The correct Answer is:

Here `T_(1)cos(90-theta)`+`T_(2)costheta=100`
And `T_(1)costheta=T_(2)cos(90-theta)`
Solving, `T_(1)=80N`

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