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In the figure, a block of weight 60N is...

In the figure, a block of weight `60N` is placed on a rough surface. The coefficient of friction between the block and the surface is `0.5` . What should be the weight `W` such that the block does not slip on the surface?

A

`60N`

B

`(60)/(sqrt(2)N`

C

`30N`

D

`(30)/(sqrt(2)N`

Text Solution

Verified by Experts

The correct Answer is:
C
Frictional force:
`F=muR=0.5xxm=0.5xx60=30N`
Now `F=T_(1)=T_(2)cos45^(@)`
or `30=T_(2)cos45^(@)`
and `W=T_(2)sin45^(@)`
Solving them we get `W=30N`
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