A worker pushes a wheelbarrow with a hor...

A worker pushes a wheelbarrow with a horizontal force of `50 N` on level ground over a distance of `5.0 m`. If a friction force on the `43 N` acts on the wheelbarrow in a direction opposite that to of worker, what work is done on the wheelbarrow by the worker?

`250 J`

`215 J`

`35 J`

`10 J`

Text Solution

Verified by Experts

The correct Answer is:

The work done on the wheebarrow by the worker is `W = (F cos theta) Delta x = (50 N) (5.0 m) = + 250 J`

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