A particle moved from position vec r(1) ...

A particle moved from position `vec r_(1) = 3 hati + 2 hatj - 6 hatk `to position`vecr_(2) = 14 hati + 13 hatj +9 hatk` undre the action of a force `(4 hati + hatj +3 hatk)` newtons . Find the work done .

`10J`

`100 J`

`0.01 J`

`1J`

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The correct Answer is:

displacement : `vec s = vec r_(2) - vec r_(1)`. Now find `W = vec F. vecs`

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