A block of mass `m` is released from the top of a mooth inclined plane of height `h` its speed at the bottom of the plane is proportion to

Options

A. `m^(0)`
B. `m`
C. `m^(2)`
D. `m^(-1)`

Answer

A

Explanation

Let `v` be the speed of the object at the bottom of the plane
According to work energy therem
`W = Delta K = K_(f) - K_(i)`
`mgh = (1)/(2) mv^(2) - (1)/(2) mv^(2) ( because u = 0)`
`mgh= (1)/(2) mv^(2) (because u = 0)`
`or v = sqrt(2gh)`
From the above experession it is clear the `v` is independent of the mass of an object